4x^2-102x+98=0

Solution for 4x^2-102x+98=0 equation:

4x^2-102x+98=0

a = 4; b = -102; c = +98;
Δ = b2-4ac
Δ = -1022-4·4·98
Δ = 8836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8836}=94$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-102)-94}{2*4}=\frac{8}{8}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-102)+94}{2*4}=\frac{196}{8}
=24+1/2
$